7 Câu trả lời
  • Captain
    Captain

    \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {y = 2x - 1} \\ 
  {x + 3y = 11} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {2x - y = 1} \\ 
  {x + 3y = 11} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {2x - y = 1} \\ 
  {2x + 6y = 22} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {2x - y = 1} \\ 
  {7y = 21} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2} \\ 
  {y = 3} 
\end{array}} \right. \hfill \\ 
\end{matrix}

    Trả lời hay
    1 Trả lời 23/08/22
    • Đen2017
      Đen2017

      \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {x + 3y - 2 = 0} \\ 
  {\dfrac{x}{2} = \dfrac{y}{3} + 1} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2 - 3y} \\ 
  {\dfrac{x}{2} = \dfrac{y}{3} + 1} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2 - 3y} \\ 
  {\dfrac{{2 - 3y}}{2} = \dfrac{y}{3} + 1} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2 - 3y} \\ 
  {3\left( {2 - 3y} \right) = 2y + 6} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2 - 3y} \\ 
  {6 - 9y = 2y + 6} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2 - 3y} \\ 
  {11y = 0} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 2} \\ 
  {y = 0} 
\end{array}} \right. \hfill \\ 
\end{matrix}

      0 Trả lời 23/08/22
      • Captain
        Captain

        \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {x\left( {x + 2} \right) - \left( {x - 2} \right)x + y = 3} \\ 
  {y\left( {2 + y} \right) = y\left( {y - 4} \right) + 3x} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {{x^2} + 2x - {x^2} + 2x + y = 3} \\ 
  {2y + {y^2} = {y^2} - 4y + 3x} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {4x + y = 3} \\ 
  {6y = 3x} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {4x + y = 3} \\ 
  {2y = x} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {4.\left( {2y} \right) + y = 3} \\ 
  {2y = x} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = \dfrac{1}{3}} \\ 
  {x = \dfrac{2}{3}} 
\end{array}} \right. \hfill \\ 
\end{matrix}

        0 Trả lời 23/08/22
        • Đen2017
          Đen2017

          \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {x = 3 - 2y} \\ 
  {y =  - 1 + 2x} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 3 - 2y} \\ 
  {y =  - 1 + 2.\left( {3 - 2y} \right)} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 3 - 2y} \\ 
  {y =  - 1 + 6 - 4y} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 3 - 2y} \\ 
  {5y = 5} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 1} \\ 
  {y = 1} 
\end{array}} \right. \hfill \\ 
\end{matrix}

          0 Trả lời 23/08/22
          • Đội Trưởng Mỹ
            Đội Trưởng Mỹ

            \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {3x = 17 - y} \\ 
  {x - 2y = 1} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {3x = 17 - y} \\ 
  {x = 1 + 2y} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {3\left( {1 + 2y} \right) = 17 - y} \\ 
  {x = 1 + 2y} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {3 + 6y = 17 - y} \\ 
  {x = 1 + 2y} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {7y = 14} \\ 
  {x = 1 + 2y} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 2} \\ 
  {x = 5} 
\end{array}} \right. \hfill \\ 
\end{matrix}

            0 Trả lời 23/08/22
            • Su kem
              Su kem

              \begin{matrix}
  \left\{ {\begin{array}{*{20}{c}}
  {y = 3 - 2x} \\ 
  {\frac{x}{4} = \frac{y}{3} - 1} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 3 - 2x} \\ 
  {\frac{x}{4} = \frac{{3 - 2x}}{3} - 1} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 3 - 2x} \\ 
  {3x = 4\left( {3 - 2x} \right) - 12} 
\end{array}} \right. \hfill \\
   \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 3 - 2x} \\ 
  {3x = 12 - 8x - 12} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 3 - 2x} \\ 
  {11x = 0} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {y = 1} \\ 
  {x = 0} 
\end{array}} \right. \hfill \\ 
\end{matrix}

              0 Trả lời 23/08/22
              • Bơ

                \left\{ {\begin{array}{*{20}{c}}
  {3x + y = 5} \\ 
  {3 - x = y} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {3x + y = 5} \\ 
  {x + y = 3} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {2x = 2} \\ 
  {x + y = 3} 
\end{array}} \right. \Leftrightarrow \left\{ {\begin{array}{*{20}{c}}
  {x = 1} \\ 
  {y = 2} 
\end{array}} \right.

                0 Trả lời 23/08/22

                Hỏi đáp Toán 9

                Xem thêm